![A first order reaction is 50% completed in 30 minutes at 300 K and in 10 minutes at 320 K, Calculate the activation energy of the reaction (R = 8.314 "JK mol"^(-1).) A first order reaction is 50% completed in 30 minutes at 300 K and in 10 minutes at 320 K, Calculate the activation energy of the reaction (R = 8.314 "JK mol"^(-1).)](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/645347630_web.png)
A first order reaction is 50% completed in 30 minutes at 300 K and in 10 minutes at 320 K, Calculate the activation energy of the reaction (R = 8.314 "JK mol"^(-1).)
21.rate of reaction increases four times when the temperature changes from 300 Kelvin to 320 Kelvin. Calculate the energy of activation of reaction assuming that it does not change with temperature
![One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm . In this One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm . In this](https://i.ytimg.com/vi/lniyXOcA4Fg/maxresdefault.jpg)
One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm . In this
![SOLVED: Boltzmann constant: kB = 1.38 x 10-28 JK Thermal energy at 300 K: kBT = 0.0259 eV Energy unit conversion: 1eV = 1.60 x 10-19 J SOLVED: Boltzmann constant: kB = 1.38 x 10-28 JK Thermal energy at 300 K: kBT = 0.0259 eV Energy unit conversion: 1eV = 1.60 x 10-19 J](https://cdn.numerade.com/ask_images/ecbef31644d74b72abe819aa8e75e40a.jpg)
SOLVED: Boltzmann constant: kB = 1.38 x 10-28 JK Thermal energy at 300 K: kBT = 0.0259 eV Energy unit conversion: 1eV = 1.60 x 10-19 J
![A carnot engine whose sink is at 300 K has an efficiency of 50. by how much should the temperature of source be increased so as the efficiency becomes 70% ? A carnot engine whose sink is at 300 K has an efficiency of 50. by how much should the temperature of source be increased so as the efficiency becomes 70% ?](https://d10lpgp6xz60nq.cloudfront.net/ss/web/1148246.jpg)