1 mole of heptane (V.P. = 92 mm of Hg) was mixed with 4 moles of octane (V.P = 31 mm of Hg). The vapour pressure of resulting ideal solution is:
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![21 When 20.0 g C2H6 [MM= 30g/mol] and g 02 [MM= 32 | Chegg.com](https://media.cheggcdn.com/study/179/179eb391-a1e3-4451-8b2d-2b0d32c918a5/image "21 When 20.0 g C2H6 [MM= 30g/mol] and g 02 [MM= 32 | Chegg.com")
21 When 20.0 g C2H6 [MM= 30g/mol] and g 02 [MM= 32 | Chegg.com
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1 mole heptane `(V.P = 92 mm of Hg)` is mixed with 4 mol. Octane `(V.P = 31` mm of `Hg)`, form an - YouTube
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SOLVED: What is the concentration in molarity of a solution which is 1.53 %m/v acetone (MM = 58.08 g/mol ) in ethanol (MM = 46.07 g/mol)?
